1. If five times the fifth term of an AP is equal to seven times, the seventh term of the AP, then what is the twelfth term?
(a) –1
(b) 0
(c) 1

(d) –2

2. Three terms are in AP such that their sum is 18. The sum of the first two terms is six more than the sum of the last two terms. Find the last term.
(a) 6
(b) 9
(c) 3
(d) 2

3. Determine k, so that (k + 2), (4k – 6) and (3k – 2) are three consecutive terms of an AP.
(a) 3
(b) 2
(c) 4
(d) 6

4. In an AP, the first term is 2 and the sum of the first five terms is one-fourth the sum of the next five terms. Find the second term.
(a) –4
(b) –10
(c) –16
(d) –12

5. The sum of four terms in an AP is 64. The product of the extreme terms is 220. Find the first and fourth term.
(a) 14, 28
(b) 10, 22
(c) 28, 14
(d) 6, 30

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