SSC Multi-Tasking Staff (Non Technical) Exam Mock Test -6 (Numerical Aptitude)
SSC Multi-Tasking Staff (Non Technical) Exam Mock Test -6 (Numerical Aptitude)
26. In an examination, a student who gets 20% of the maximum marks fails by 5 marks. Another student who scores 30% of the maximum marks gets 20 marks more than the pass marks. The necessary percentage required for passing is
(a) 32%
(b) 23%
(c) 22%
(d) 20%
27. When 60 is subtracted from 60% of a number, the result is 60. The number is
(a) 120
(b) 150
(c) 180
(d) 200
28.
32. I f 1 7 200 is divided by 18, the remainder is :
(a) 17
(b) 16
(c) 1
(d) 2
33. On simplification 3034 – (1002 ÷ 20.04) is equal to
(a) 3029
(b) 2984
(c) 2993
(d) 2543
35. When simplified, the expression
(a) 1.6
(b) 0.8
(c) 1.0
(d) 0
36.
(a) 350
(b) 785
(c) 1220
(d) 1320
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एसएससी मल्टीटास्किंग (गैर तकनीकी) स्टाफ परीक्षा के लिए अध्ययन सामग्री
37. Find the missing number of the sequence : “3, 14, 25, 36, 47 , ?”
(a) 1114
(b) 1111
(c) 1113
(d) None of these
38. When simplified the product
39. The sum (101 + 102 + 103 + ... + 200) is equal to :
(a) 15000
(b) 15025
(c) 15050
(d) 25000
40. The sum of all natural numbers from 75 to 97 is:
(a) 1598
(b) 1798
(c) 1958
(d) 1978
(a) 52°, 38°
(b) 56°, 34°
(c) 51°, 39°
(d) 57°, 33°
(a) 34°
(b) 33°
(c) 35°
(d) 38°
43. The point of intersection of the line x + y + 1 = 0 and 2x – y + 5 = 0 is
(a) (–1, 1)
(b) (–2, 1)
(c) (1, 2)
(d) (1, –2)
44 The equation of the line passing through the point of intersection of the lines 5x – 2y = 3, 4x – 7y + 3 = 0 and parallel to the lines 3x – 2y + 5 = 0
(a) 3x – 2y = 0
(b) 3x – 2y =1
(c) 3x – 2y = 5
(d) None of these
45 The equation of a straight line passing through the intersection of the lines x + y + 1 = 0, 2x – y + 5 = 0 and through the point (5, –2).
(a) 3x + 5y = 1
(b) 3x – 7y =1
(c) 3x + 7y = 1
(d) None of these
46. The equation of a line parallel to 3x – 2y + 1 = 0 and passing through the origin is
(a) 3x – 2y = 0
(b) 3x – 2y = 5
(c) 3x – 2y = 1
(d) None of these
48. If the polynomials f(x) = x3 – ax2 + 9x + a is divided by (x – a).
(a) 10a
(b) 6a
(c) 7a
(d) 5a
49. If x2 – 1 is a factor of the polynomial f(x) = 2x2 + Ax2 + Bx + 3, then find A and B.
(a) –3,2
(b) –3, –2
(c) 3,–2
(d) Can’t be determined
50. When 4x3 – ax2 + bx – 4 is divided by x – 2 and x + 1, the respective remainders are 20 and –13. Find the values of a and b
(a) –3, –2
(b) –3,2
(c) 3, –2
(d) 3, 2
